time and distance Model Questions & Answers, Practice Test for ssc mts paper 1 2023
ssc mts paper 1 2023 SYLLABUS WISE SUBJECTS MCQs
Number System
LCM & HCF
Ratio Proportion & Partnership
Percentages
Profit & Loss
Time & Work
Time & Distance
Simple Interest & Compound Interest
Mensuration: Area & Volumes
Algebraic Expressions
Trigonometric Ratios & Identity
A 300 meter long train moving with an average speed of 126 km/hr crosses a platform in 24 seconds. A man crosses the same platform in 5 minutes. What is the speed of the man in meters/second
Answer: (c)
Length of platform
= $126×5/18×24–300$ = 540 meter
∴ Speed of man = $540/{5×60}$
= 1.8 meter/second
The ratio between the speed of a train and a car is 16 : 15 respectively. Also, a bus covered a distance of 480 km in 8 h. The speed of the bus is three-fourth the speed of the train. How much distance will the car cover in 6 h?
Answer: (c)
Speed of bus = ${480}/8$ = 60km/h
Speed of train = ${60 × 4}/3$ = 80 km/h
Speed of train : Speed of car = 16 : 15
∴ Speed of car = ${80}/{16}$ × 15 = 75 km/h
Distance covered by car in 6 h r = 75 × 6 = 450 km
Car A runs at the speed of 65 km/h and reaches its destination in 8h. Car B runs at the speed of 70 km/h and reaches its destination in 4h. What is the respective ratio of distances covered by Car A and Car B ?
Answer: (b)
Distance travelled by Car A = 65 × 8 = 520 km
Distance travelled by Car B = 70 × 4 = 280 km
Ratio = ${520}/{280}$ = 13 : 7
Two men start together to walk a certain distance, one at 3 $3/4$ km an hour and the other at 3 km an hour. The former arrives half an hour before the latter. Find the distance.
Answer: (a)
Distance = ${\text"Time difference" × S_1 × S_2}/{S_1 - S_2}$
Where, $S_1 and S_2$ are the speeds of the two persons.
∴ distance = ${{1/2} × 3 × {15}/{4}}/{{{15}/4}-3} = {15}/2$ = 7.5km
Subbu starts from a point O at 10:00 a.m., overtakes Ajay, who is moving in the same direction, at 11:00 a.m. and Bhuvan moving in the opposite direction at 12:00 (noon). If the speed of Bhuvan is one fourth the speed of Subbu, at what time will Ajay and Bhuvan cross each other ?
Answer: (d)
Let the speed of Ajay be V and the speed of Bhuvan and Subbu be 1 and 4 respectively.
Then OA = 4 and OB = 4.
At 12:00 noon.
![time-speed-and-distance-mcq-problems-competitive-exams-quantitative-aptitude time-speed-and-distance-mcq-problems-competitive-exams-quantitative-aptitude](https://careericons.com/adminicon/bunch/images/time-speed-and-distance-mcq-problems-competitive-exams-25.png)
Let Ajay be at C at 12:00 noon at a distance of V from A (towards B)
∴Time taken for them to meet from 12:00 noon.
= ${4-V}/{1+V}$
Since V is not known ${4-V}/{1+V}$ cannot be determined.
ssc mts paper 1 2023 IMPORTANT QUESTION AND ANSWERS
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